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2018—2019学年度第一学期期末学习诊断检测
八年级数学试题参考答案
一、 单项选择题(共12小题,每小题4分,满分48分)
1
2
3
4
5
6
7
8
9
10
11
12
A
B
D
C
C
A
C
D
A
B
A
B
二、填空题(共6小题,每小题4分,满分24分)
13. 2 14. (-1,-3) 15. 87
16. 240° 17. (3,0) 18. (0,21009)
三、解答题(共9小题,满分78分,解答应写出文字说明,证明过程或演算步骤)
19. 计算:(本题满分8分,每小题4分)
(1) = ·······························2分
= ····························································4分
(2) =··············1分
=··················································2分
=·······················································3分
= -1 ·····························································4分
20. 解方程组: (本题满分8分,每小题4分)
(1)
解:得 ③
得 ④
得 ·······································2分
将代入①,得
········································3分
所以原方程组的解是···········································4分
(2)
解: 得 ······················2分
将代入①,得 ·······················3分
所以原方程组的解是········································4分
20. (本题满分6分)
证明:∵
∴ ·························1分
∴ ······················2分
又∵
∴························4分
∴ ·························5分
∴····························6分
21. (本题满分6分)
解:∵ BE平分∠ABC
∴ ·······················1分
又∵ DE∥BC
∴ ························2分
∴ ························4分
∴ ·····················5分
∵点D是AB的中点
∴ ················6分
23.(本题满分8分)
(1)众数___90_____,中位数___90_____;·································2分
(2)
···2分
(3)由题意可得,轻度污染的天数为30-3-15=12(天)················1分
下图是补全后的空气质量天数条形统计图
······························2分
(4)空气污染指数在100以下的天数为(天)··············1分
所以:该市居民一年中适合做户外运动天数:(天)············2分
24.(本题满分8分)
解:(1)·································2分
(2)················································2分
(3)
·································2分
所以 ,所以△EFG为直角三角形······················3分
又因为 ,所以△EFG为等腰直角三角形··························4分
25.(本题满分10分)
解:(1)设本次试点投放的A型车x辆,B型车y辆··························1分
由题意可得: ······························3分
解 得··················································4分
所以: 本次试点投放的A型车60辆,B型车40辆··························5分
(2)设 B型车购进a辆,购车总费用为w元
则
=················································2分
∵
∴ w随a的增大而减小
∴当a取最大值300时,w有最小值,
此时,购进A型车:500-300=200(辆)······································3分
∴ (元)···························4分
所以:当购进A型车200辆,B型车300辆时,购车费用最低,
最低费用为176000元。 ··········································5分
26.(本题满分12分)
解:(1)在中
令,则 ············································1分
∴B点坐标为:···················································2分
令,则,解得··································3分
∴A点坐标为:····················································4分
(2)过点P做x轴的垂线,交x轴于点M
∵A点坐标为:,∴·········1分
∵△中,
∴···············2分
把代入中,得
∴P点坐标为:··················3分
把P代入中,
可得: 解得:···········4分
(3)∵C是直线上一点
∴设C点坐标为
则点D坐标为,点E坐标为······················1分
∴
···········································2分
∵CD=2ED
∴=
解得······················································3分
则
此时,C点坐标为········································4分
27.(本题满分12分)
解(1)∵OA=6,OB=10 ∴C点坐标为(6,10)
即此时P点坐标为(6,10)··················1分
设直线DP解析式为
代入D点坐标(0,2),P点坐标(6,10)
可得:····················2分
解,得························································3分
∴直线DP解析式为···········································4分
(2)若点P在线段AC上运动,则△OPD面积是一个定值:=6·····1分
所以若△OPD的面积为4,则点P位于线段CB上
此时 ················································2分
可得:·························································3分
此时点P运动的路程:10+6-4=12·········································4分
所以点P运动的时间:
(秒) ··································5分
(3)3或或 ············································3分
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